1/x+1=5/2x-4

Solution for 1/x+1=5/2x-4 equation:

1/x+1=5/2x-4

We move all terms to the left:

1/x+1-(5/2x-4)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x-4)!=0

x∈R


We get rid of parentheses

1/x-5/2x+4+1=0

We calculate fractions


2x/2x^2+(-5x)/2x^2+4+1=0

We add all the numbers together, and all the variables

2x/2x^2+(-5x)/2x^2+5=0

We multiply all the terms by the denominator


2x+(-5x)+5*2x^2=0

Wy multiply elements

10x^2+2x+(-5x)=0

We get rid of parentheses

10x^2+2x-5x=0

We add all the numbers together, and all the variables

10x^2-3x=0

a = 10; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·10·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*10}=\frac{0}{20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*10}=\frac{6}{20}
=3/10
$