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5x+4/8x+5=34
We move all terms to the left:
5x+4/8x+5-(34)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
5x+4/8x-29=0
We multiply all the terms by the denominator
5x*8x-29*8x+4=0
Wy multiply elements
40x^2-232x+4=0
a = 40; b = -232; c = +4;
Δ = b2-4ac
Δ = -2322-4·40·4
Δ = 53184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{53184}=\sqrt{64*831}=\sqrt{64}*\sqrt{831}=8\sqrt{831}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-232)-8\sqrt{831}}{2*40}=\frac{232-8\sqrt{831}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-232)+8\sqrt{831}}{2*40}=\frac{232+8\sqrt{831}}{80} $
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