3(v-8)+2(v+5)=7(v-4)

Solution for 3(v-8)+2(v+5)=7(v-4) equation:

3(v-8)+2(v+5)=7(v-4)

We move all terms to the left:

3(v-8)+2(v+5)-(7(v-4))=0

We multiply parentheses

3v+2v-(7(v-4))-24+10=0


We calculate terms in parentheses: -(7(v-4)), so:

7(v-4)

We multiply parentheses

7v-28

Back to the equation:

-(7v-28)


We add all the numbers together, and all the variables

5v-(7v-28)-14=0

We get rid of parentheses

5v-7v+28-14=0

We add all the numbers together, and all the variables

-2v+14=0

We move all terms containing v to the left, all other terms to the right

-2v=-14

v=-14/-2

v=+7