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3(x+3)-2(x+-1)=5(x+-5)
We move all terms to the left:
3(x+3)-2(x+-1)-(5(x+-5))=0
We add all the numbers together, and all the variables
3(x+3)-2(x-1)-(5(x-5))=0
We multiply parentheses
3x-2x-(5(x-5))+9+2=0
We calculate terms in parentheses: -(5(x-5)), so:We add all the numbers together, and all the variables
5(x-5)
We multiply parentheses
5x-25
Back to the equation:
-(5x-25)
x-(5x-25)+11=0
We get rid of parentheses
x-5x+25+11=0
We add all the numbers together, and all the variables
-4x+36=0
We move all terms containing x to the left, all other terms to the right
-4x=-36
x=-36/-4
x=+9
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