4(k+4)+13(k-1)=-3(k-3)+14

Solution for 4(k+4)+13(k-1)=-3(k-3)+14 equation:

4(k+4)+13(k-1)=-3(k-3)+14

We move all terms to the left:

4(k+4)+13(k-1)-(-3(k-3)+14)=0

We multiply parentheses

4k+13k-(-3(k-3)+14)+16-13=0


We calculate terms in parentheses: -(-3(k-3)+14), so:

-3(k-3)+14

We multiply parentheses

-3k+9+14

We add all the numbers together, and all the variables

-3k+23

Back to the equation:

-(-3k+23)


We add all the numbers together, and all the variables

17k-(-3k+23)+3=0

We get rid of parentheses

17k+3k-23+3=0

We add all the numbers together, and all the variables

20k-20=0

We move all terms containing k to the left, all other terms to the right

20k=20

k=20/20

k=1