1/4(2n-8)+1/3n=1/2(n+6)

Solution for 1/4(2n-8)+1/3n=1/2(n+6) equation:

1/4(2n-8)+1/3n=1/2(n+6)

We move all terms to the left:

1/4(2n-8)+1/3n-(1/2(n+6))=0


Domain of the equation: 4(2n-8)!=0

n∈R



Domain of the equation: 3n!=0

n!=0/3

n!=0

n∈R



Domain of the equation: 2(n+6))!=0

n∈R


We calculate fractions


12n^2/(4(2n-8)*3n*2(n+6)))+(8n^22/(4(2n-8)*3n*2(n+6)))+(-(1*4(2n-8)*3n)/(4(2n-8)*3n*2(n+6)))=0


We calculate terms in parentheses: -(1*4(2n-8)*3n)/(4(2n-8)*3n*2(n+6))), so:

1*4(2n-8)*3n)/(4(2n-8)*3n*2(n+6))

We multiply all the terms by the denominator


1*4(2n-8)*3n)

Wy multiply elements

12n^2(2

Back to the equation:

-(12n^2(2)


We do not support enpression: n^22