5+1/3(9y-12)=1/4(y=18+1/6y)

Solution for 5+1/3(9y-12)=1/4(y=18+1/6y) equation:

5+1/3(9y-12)=1/4(y=18+1/6y)

We move all terms to the left:

5+1/3(9y-12)-(1/4(y)=0


Domain of the equation: 3(9y-12)!=0

y∈R



Domain of the equation: 4y+5!=0

We move all terms containing y to the left, all other terms to the right

4y!=-5

y!=-5/4

y!=-1+1/4

y∈R


We calculate fractions


(4y+5)/(108y^2-144y+5)+(-3y9/(108y^2-144y+5)=0


We calculate terms in parentheses: +(-3y9/(108y^2-144y+5), so:

-3y9/(108y^2-144y+5

We multiply all the terms by the denominator


-3y9

We add all the numbers together, and all the variables

-3y^9

We do not support eypression: y^9