p+3/4(p-8)=11+1/4(12p+4)

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Solution for p+3/4(p-8)=11+1/4(12p+4) equation: 



p+3/4(p-8)=11+1/4(12p+4)

We move all terms to the left:

p+3/4(p-8)-(11+1/4(12p+4))=0



Domain of the equation: 4(p-8)!=0

p∈R





Domain of the equation: 4(12p+4))!=0

p∈R



We calculate fractions


p+(12p1/(4(p-8)*4(12p+4)))+(-4pp/(4(p-8)*4(12p+4)))=0



We calculate terms in parentheses: +(12p1/(4(p-8)*4(12p+4))), so:

12p1/(4(p-8)*4(12p+4))

We multiply all the terms by the denominator


12p1

We add all the numbers together, and all the variables

12p

Back to the equation:

+(12p)





We calculate terms in parentheses: +(-4pp/(4(p-8)*4(12p+4))), so:

-4pp/(4(p-8)*4(12p+4))

We multiply all the terms by the denominator


-4pp

Back to the equation:

+(-4pp)



We add all the numbers together, and all the variables

13p+(-4pp)=0

We get rid of parentheses

13p-4pp=0

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