2/3y+12=-10

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Solution for 2/3y+12=-10 equation: 



2/3y+12=-10

We move all terms to the left:

2/3y+12-(-10)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

2/3y+22=0

We multiply all the terms by the denominator


22*3y+2=0

Wy multiply elements

66y+2=0

We move all terms containing y to the left, all other terms to the right

66y=-2

y=-2/66

y=-1/33

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