12=3z-4z+6

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Solution for 12=3z-4z+6 equation:



12=3z-4z+6
We move all terms to the left:
12-(3z-4z+6)=0
We add all the numbers together, and all the variables
-(-1z+6)+12=0
We get rid of parentheses
1z-6+12=0
We add all the numbers together, and all the variables
z+6=0
We move all terms containing z to the left, all other terms to the right
z=-6

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