1.5x2+x-8.2=0

Solution for 1.5x2+x-8.2=0 equation:

1.5x^2+x-8.2=0

a = 1.5; b = 1; c = -8.2;
Δ = b2-4ac
Δ = 12-4·1.5·(-8.2)
Δ = 50.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{50.2}}{2*1.5}=\frac{-1-\sqrt{50.2}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{50.2}}{2*1.5}=\frac{-1+\sqrt{50.2}}{3}
$