6(3n+1)-3(1+2n)=n+2n

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Solution for 6(3n+1)-3(1+2n)=n+2n equation: 



6(3n+1)-3(1+2n)=n+2n

We move all terms to the left:

6(3n+1)-3(1+2n)-(n+2n)=0

We add all the numbers together, and all the variables

6(3n+1)-3(2n+1)-(+3n)=0

We multiply parentheses

18n-6n-(+3n)+6-3=0

We get rid of parentheses

18n-6n-3n+6-3=0

We add all the numbers together, and all the variables

9n+3=0

We move all terms containing n to the left, all other terms to the right

9n=-3

n=-3/9

n=-1/3

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