9(4z-6)=2(-3-2z)

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Solution for 9(4z-6)=2(-3-2z) equation: 



9(4z-6)=2(-3-2z)

We move all terms to the left:

9(4z-6)-(2(-3-2z))=0

We add all the numbers together, and all the variables

9(4z-6)-(2(-2z-3))=0

We multiply parentheses

36z-(2(-2z-3))-54=0



We calculate terms in parentheses: -(2(-2z-3)), so:

2(-2z-3)

We multiply parentheses

-4z-6

Back to the equation:

-(-4z-6)



We get rid of parentheses

36z+4z+6-54=0

We add all the numbers together, and all the variables

40z-48=0

We move all terms containing z to the left, all other terms to the right

40z=48

z=48/40

z=1+1/5

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