-3(u+1)=3u-9+3(2u+1)

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Solution for -3(u+1)=3u-9+3(2u+1) equation:



-3(u+1)=3u-9+3(2u+1)
We move all terms to the left:
-3(u+1)-(3u-9+3(2u+1))=0
We multiply parentheses
-3u-(3u-9+3(2u+1))-3=0
We calculate terms in parentheses: -(3u-9+3(2u+1)), so:
3u-9+3(2u+1)
determiningTheFunctionDomain 3u+3(2u+1)-9
We multiply parentheses
3u+6u+3-9
We add all the numbers together, and all the variables
9u-6
Back to the equation:
-(9u-6)
We get rid of parentheses
-3u-9u+6-3=0
We add all the numbers together, and all the variables
-12u+3=0
We move all terms containing u to the left, all other terms to the right
-12u=-3
u=-3/-12
u=1/4

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