2(y+4)=-3(3y-8)+5y

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Solution for 2(y+4)=-3(3y-8)+5y equation: 



2(y+4)=-3(3y-8)+5y

We move all terms to the left:

2(y+4)-(-3(3y-8)+5y)=0

We multiply parentheses

2y-(-3(3y-8)+5y)+8=0



We calculate terms in parentheses: -(-3(3y-8)+5y), so:

-3(3y-8)+5y

We add all the numbers together, and all the variables

5y-3(3y-8)

We multiply parentheses

5y-9y+24

We add all the numbers together, and all the variables

-4y+24

Back to the equation:

-(-4y+24)



We get rid of parentheses

2y+4y-24+8=0

We add all the numbers together, and all the variables

6y-16=0

We move all terms containing y to the left, all other terms to the right

6y=16

y=16/6

y=2+2/3

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