-3(u+2)=4u-9+3(3u+3)

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Solution for -3(u+2)=4u-9+3(3u+3) equation: 



-3(u+2)=4u-9+3(3u+3)

We move all terms to the left:

-3(u+2)-(4u-9+3(3u+3))=0

We multiply parentheses

-3u-(4u-9+3(3u+3))-6=0



We calculate terms in parentheses: -(4u-9+3(3u+3)), so:

4u-9+3(3u+3)

determiningTheFunctionDomain
4u+3(3u+3)-9

We multiply parentheses

4u+9u+9-9

We add all the numbers together, and all the variables

13u

Back to the equation:

-(13u)



We add all the numbers together, and all the variables

-16u-6=0

We move all terms containing u to the left, all other terms to the right

-16u=6

u=6/-16

u=-3/8

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