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2y+3-2(-6y-3)=2(y-3)
We move all terms to the left:
2y+3-2(-6y-3)-(2(y-3))=0
We multiply parentheses
2y+12y-(2(y-3))+6+3=0
We calculate terms in parentheses: -(2(y-3)), so:We add all the numbers together, and all the variables
2(y-3)
We multiply parentheses
2y-6
Back to the equation:
-(2y-6)
14y-(2y-6)+9=0
We get rid of parentheses
14y-2y+6+9=0
We add all the numbers together, and all the variables
12y+15=0
We move all terms containing y to the left, all other terms to the right
12y=-15
y=-15/12
y=-1+1/4
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