2+3(2y-1)=-2(3y-7)+3y

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Solution for 2+3(2y-1)=-2(3y-7)+3y equation:



2+3(2y-1)=-2(3y-7)+3y
We move all terms to the left:
2+3(2y-1)-(-2(3y-7)+3y)=0
We multiply parentheses
6y-(-2(3y-7)+3y)-3+2=0
We calculate terms in parentheses: -(-2(3y-7)+3y), so:
-2(3y-7)+3y
We add all the numbers together, and all the variables
3y-2(3y-7)
We multiply parentheses
3y-6y+14
We add all the numbers together, and all the variables
-3y+14
Back to the equation:
-(-3y+14)
We add all the numbers together, and all the variables
6y-(-3y+14)-1=0
We get rid of parentheses
6y+3y-14-1=0
We add all the numbers together, and all the variables
9y-15=0
We move all terms containing y to the left, all other terms to the right
9y=15
y=15/9
y=1+2/3

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