-2(5y-7)+6y=2+2(2y-3)

Solution for -2(5y-7)+6y=2+2(2y-3) equation:

-2(5y-7)+6y=2+2(2y-3)

We move all terms to the left:

-2(5y-7)+6y-(2+2(2y-3))=0

We add all the numbers together, and all the variables

6y-2(5y-7)-(2+2(2y-3))=0

We multiply parentheses

6y-10y-(2+2(2y-3))+14=0


We calculate terms in parentheses: -(2+2(2y-3)), so:

2+2(2y-3)

determiningTheFunctionDomain
2(2y-3)+2

We multiply parentheses

4y-6+2

We add all the numbers together, and all the variables

4y-4

Back to the equation:

-(4y-4)


We add all the numbers together, and all the variables

-4y-(4y-4)+14=0

We get rid of parentheses

-4y-4y+4+14=0

We add all the numbers together, and all the variables

-8y+18=0

We move all terms containing y to the left, all other terms to the right

-8y=-18

y=-18/-8

y=2+1/4