-2(4u-4)+2u=6+2(3u-7)

Solution for -2(4u-4)+2u=6+2(3u-7) equation:

-2(4u-4)+2u=6+2(3u-7)

We move all terms to the left:

-2(4u-4)+2u-(6+2(3u-7))=0

We add all the numbers together, and all the variables

2u-2(4u-4)-(6+2(3u-7))=0

We multiply parentheses

2u-8u-(6+2(3u-7))+8=0


We calculate terms in parentheses: -(6+2(3u-7)), so:

6+2(3u-7)

determiningTheFunctionDomain
2(3u-7)+6

We multiply parentheses

6u-14+6

We add all the numbers together, and all the variables

6u-8

Back to the equation:

-(6u-8)


We add all the numbers together, and all the variables

-6u-(6u-8)+8=0

We get rid of parentheses

-6u-6u+8+8=0

We add all the numbers together, and all the variables

-12u+16=0

We move all terms containing u to the left, all other terms to the right

-12u=-16

u=-16/-12

u=1+1/3