2(y+3)=9y+13

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Solution for 2(y+3)=9y+13 equation:



2(y+3)=9y+13
We move all terms to the left:
2(y+3)-(9y+13)=0
We multiply parentheses
2y-(9y+13)+6=0
We get rid of parentheses
2y-9y-13+6=0
We add all the numbers together, and all the variables
-7y-7=0
We move all terms containing y to the left, all other terms to the right
-7y=7
y=7/-7
y=-1

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