2(u-4)-7=-4(-4u+3)-5u

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Solution for 2(u-4)-7=-4(-4u+3)-5u equation: 



2(u-4)-7=-4(-4u+3)-5u

We move all terms to the left:

2(u-4)-7-(-4(-4u+3)-5u)=0

We multiply parentheses

2u-(-4(-4u+3)-5u)-8-7=0



We calculate terms in parentheses: -(-4(-4u+3)-5u), so:

-4(-4u+3)-5u

We add all the numbers together, and all the variables

-5u-4(-4u+3)

We multiply parentheses

-5u+16u-12

We add all the numbers together, and all the variables

11u-12

Back to the equation:

-(11u-12)



We add all the numbers together, and all the variables

2u-(11u-12)-15=0

We get rid of parentheses

2u-11u+12-15=0

We add all the numbers together, and all the variables

-9u-3=0

We move all terms containing u to the left, all other terms to the right

-9u=3

u=3/-9

u=-1/3

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