5(2x-3)=(4+7x)+8

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Solution for 5(2x-3)=(4+7x)+8 equation: 



5(2x-3)=(4+7x)+8

We move all terms to the left:

5(2x-3)-((4+7x)+8)=0

We add all the numbers together, and all the variables

5(2x-3)-((7x+4)+8)=0

We multiply parentheses

10x-((7x+4)+8)-15=0



We calculate terms in parentheses: -((7x+4)+8), so:

(7x+4)+8

We get rid of parentheses

7x+4+8

We add all the numbers together, and all the variables

7x+12

Back to the equation:

-(7x+12)



We get rid of parentheses

10x-7x-12-15=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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