-2(5c+2)-2c=3(2c+3)+7

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Solution for -2(5c+2)-2c=3(2c+3)+7 equation: 



-2(5c+2)-2c=3(2c+3)+7

We move all terms to the left:

-2(5c+2)-2c-(3(2c+3)+7)=0

We add all the numbers together, and all the variables

-2c-2(5c+2)-(3(2c+3)+7)=0

We multiply parentheses

-2c-10c-(3(2c+3)+7)-4=0



We calculate terms in parentheses: -(3(2c+3)+7), so:

3(2c+3)+7

We multiply parentheses

6c+9+7

We add all the numbers together, and all the variables

6c+16

Back to the equation:

-(6c+16)



We add all the numbers together, and all the variables

-12c-(6c+16)-4=0

We get rid of parentheses

-12c-6c-16-4=0

We add all the numbers together, and all the variables

-18c-20=0

We move all terms containing c to the left, all other terms to the right

-18c=20

c=20/-18

c=-1+1/9

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