288=x+4+4x+10(x-1)

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Solution for 288=x+4+4x+10(x-1) equation: 



288=x+4+4x+10(x-1)

We move all terms to the left:

288-(x+4+4x+10(x-1))=0



We calculate terms in parentheses: -(x+4+4x+10(x-1)), so:

x+4+4x+10(x-1)

determiningTheFunctionDomain
x+4x+10(x-1)+4

We add all the numbers together, and all the variables

5x+10(x-1)+4

We multiply parentheses

5x+10x-10+4

We add all the numbers together, and all the variables

15x-6

Back to the equation:

-(15x-6)



We get rid of parentheses

-15x+6+288=0

We add all the numbers together, and all the variables

-15x+294=0

We move all terms containing x to the left, all other terms to the right

-15x=-294

x=-294/-15

x=19+3/5

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