8(2x-3)-2=2-8(3x-2)

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Solution for 8(2x-3)-2=2-8(3x-2) equation: 



8(2x-3)-2=2-8(3x-2)

We move all terms to the left:

8(2x-3)-2-(2-8(3x-2))=0

We multiply parentheses

16x-(2-8(3x-2))-24-2=0



We calculate terms in parentheses: -(2-8(3x-2)), so:

2-8(3x-2)

determiningTheFunctionDomain
-8(3x-2)+2

We multiply parentheses

-24x+16+2

We add all the numbers together, and all the variables

-24x+18

Back to the equation:

-(-24x+18)



We add all the numbers together, and all the variables

16x-(-24x+18)-26=0

We get rid of parentheses

16x+24x-18-26=0

We add all the numbers together, and all the variables

40x-44=0

We move all terms containing x to the left, all other terms to the right

40x=44

x=44/40

x=1+1/10

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