(16x-4)+(9x-6)=122

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Solution for (16x-4)+(9x-6)=122 equation: 



(16x-4)+(9x-6)=122

We move all terms to the left:

(16x-4)+(9x-6)-(122)=0

We get rid of parentheses

16x+9x-4-6-122=0

We add all the numbers together, and all the variables

25x-132=0

We move all terms containing x to the left, all other terms to the right

25x=132

x=132/25

x=5+7/25

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