(7x-17)=(3x-7)+(x+20)

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Solution for (7x-17)=(3x-7)+(x+20) equation: 



(7x-17)=(3x-7)+(x+20)

We move all terms to the left:

(7x-17)-((3x-7)+(x+20))=0

We get rid of parentheses

7x-((3x-7)+(x+20))-17=0



We calculate terms in parentheses: -((3x-7)+(x+20)), so:

(3x-7)+(x+20)

We get rid of parentheses

3x+x-7+20

We add all the numbers together, and all the variables

4x+13

Back to the equation:

-(4x+13)



We get rid of parentheses

7x-4x-13-17=0

We add all the numbers together, and all the variables

3x-30=0

We move all terms containing x to the left, all other terms to the right

3x=30

x=30/3

x=10

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