(3x-7)=(x+20)+(7x-17)

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Solution for (3x-7)=(x+20)+(7x-17) equation: 



(3x-7)=(x+20)+(7x-17)

We move all terms to the left:

(3x-7)-((x+20)+(7x-17))=0

We get rid of parentheses

3x-((x+20)+(7x-17))-7=0



We calculate terms in parentheses: -((x+20)+(7x-17)), so:

(x+20)+(7x-17)

We get rid of parentheses

x+7x+20-17

We add all the numbers together, and all the variables

8x+3

Back to the equation:

-(8x+3)



We get rid of parentheses

3x-8x-3-7=0

We add all the numbers together, and all the variables

-5x-10=0

We move all terms containing x to the left, all other terms to the right

-5x=10

x=10/-5

x=-2

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