(1/4)(x-7)=1+3x

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Solution for (1/4)(x-7)=1+3x equation:



(1/4)(x-7)=1+3x
We move all terms to the left:
(1/4)(x-7)-(1+3x)=0
Domain of the equation: 4)(x-7)!=0
x∈R
We add all the numbers together, and all the variables
(+1/4)(x-7)-(3x+1)=0
We get rid of parentheses
(+1/4)(x-7)-3x-1=0
We multiply parentheses ..
(+x^2+1/4*-7)-3x-1=0
We multiply all the terms by the denominator
(+x^2+1-3x*4*-7)-1*4*-7)=0
We add all the numbers together, and all the variables
(+x^2+1-3x*4*-7)=0
We get rid of parentheses
x^2-3x*4*+1-7=0
We add all the numbers together, and all the variables
x^2-3x*4*-6=0
Wy multiply elements
x^2-12x^2-6=0
We add all the numbers together, and all the variables
-11x^2-6=0
a = -11; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·(-11)·(-6)
Δ = -264
Delta is less than zero, so there is no solution for the equation

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