(3x-7)=(x+20)+(3x-7)

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Solution for (3x-7)=(x+20)+(3x-7) equation: 



(3x-7)=(x+20)+(3x-7)

We move all terms to the left:

(3x-7)-((x+20)+(3x-7))=0

We get rid of parentheses

3x-((x+20)+(3x-7))-7=0



We calculate terms in parentheses: -((x+20)+(3x-7)), so:

(x+20)+(3x-7)

We get rid of parentheses

x+3x+20-7

We add all the numbers together, and all the variables

4x+13

Back to the equation:

-(4x+13)



We get rid of parentheses

3x-4x-13-7=0

We add all the numbers together, and all the variables

-1x-20=0

We move all terms containing x to the left, all other terms to the right

-x=20

x=20/-1

x=-20

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