x2=3.5

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Solution for x2=3.5 equation:



x2=3.5
We move all terms to the left:
x2-(3.5)=0
We add all the numbers together, and all the variables
x^2-3.5=0
a = 1; b = 0; c = -3.5;
Δ = b2-4ac
Δ = 02-4·1·(-3.5)
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{14}}{2*1}=\frac{0-\sqrt{14}}{2} =-\frac{\sqrt{}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{14}}{2*1}=\frac{0+\sqrt{14}}{2} =\frac{\sqrt{}}{2} $

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