(6-3i)*(2+5i)*(6-2i)=0

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Solution for (6-3i)*(2+5i)*(6-2i)=0 equation: 



(6-3i)(2+5i)(6-2i)=0

We add all the numbers together, and all the variables

(-3i+6)(5i+2)(-2i+6)=0

We multiply parentheses ..

(-15i^2-6i+30i+12)(-2i+6)=0

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