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(2x-1)(5x-5)=0
We multiply parentheses ..
(+10x^2-10x-5x+5)=0
We get rid of parentheses
10x^2-10x-5x+5=0
We add all the numbers together, and all the variables
10x^2-15x+5=0
a = 10; b = -15; c = +5;
Δ = b2-4ac
Δ = -152-4·10·5
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5}{2*10}=\frac{10}{20} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5}{2*10}=\frac{20}{20} =1 $
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