(2x*x*x*x-34)*(3-x)=2(x-3)

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Solution for (2x*x*x*x-34)*(3-x)=2(x-3) equation:



(2x*x*x*x-34)(3-x)=2(x-3)
We move all terms to the left:
(2x*x*x*x-34)(3-x)-(2(x-3))=0
We add all the numbers together, and all the variables
(2x*x*x*x-34)(-1x+3)-(2(x-3))=0
We multiply parentheses ..
(-2x^5+6x^4+34x-102)-(2(x-3))=0
We calculate terms in parentheses: -(2(x-3)), so:
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
We do not support expression: x^5

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