4+2x/6x=12/5x=2/25

Solution for 4+2x/6x=12/5x=2/25 equation:

4+2x/6x=12/5x=2/25

We move all terms to the left:

4+2x/6x-(12/5x)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x/6x-(+12/5x)+4=0

We get rid of parentheses

2x/6x-12/5x+4=0

We calculate fractions


10x^2/30x^2+(-72x)/30x^2+4=0

We multiply all the terms by the denominator


10x^2+(-72x)+4*30x^2=0

Wy multiply elements

10x^2+120x^2+(-72x)=0

We get rid of parentheses

10x^2+120x^2-72x=0

We add all the numbers together, and all the variables

130x^2-72x=0

a = 130; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·130·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*130}=\frac{0}{260}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*130}=\frac{144}{260}
=36/65
$