3(y+3)=6(y-1)

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Solution for 3(y+3)=6(y-1) equation: 



3(y+3)=6(y-1)

We move all terms to the left:

3(y+3)-(6(y-1))=0

We multiply parentheses

3y-(6(y-1))+9=0



We calculate terms in parentheses: -(6(y-1)), so:

6(y-1)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We get rid of parentheses

3y-6y+6+9=0

We add all the numbers together, and all the variables

-3y+15=0

We move all terms containing y to the left, all other terms to the right

-3y=-15

y=-15/-3

y=+5

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