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(3x+10)(4x-15)=180
We move all terms to the left:
(3x+10)(4x-15)-(180)=0
We multiply parentheses ..
(+12x^2-45x+40x-150)-180=0
We get rid of parentheses
12x^2-45x+40x-150-180=0
We add all the numbers together, and all the variables
12x^2-5x-330=0
a = 12; b = -5; c = -330;
Δ = b2-4ac
Δ = -52-4·12·(-330)
Δ = 15865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{15865}}{2*12}=\frac{5-\sqrt{15865}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{15865}}{2*12}=\frac{5+\sqrt{15865}}{24} $
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