(3a+12)+(a+40)=180

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Solution for (3a+12)+(a+40)=180 equation: 



(3a+12)+(a+40)=180

We move all terms to the left:

(3a+12)+(a+40)-(180)=0

We get rid of parentheses

3a+a+12+40-180=0

We add all the numbers together, and all the variables

4a-128=0

We move all terms containing a to the left, all other terms to the right

4a=128

a=128/4

a=32

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