(2x-1)/x-5+3=(3x-2)/5-x

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Solution for (2x-1)/x-5+3=(3x-2)/5-x equation: 



(2x-1)/x-5+3=(3x-2)/5-x

We move all terms to the left:

(2x-1)/x-5+3-((3x-2)/5-x)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 5-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-5

x!=-5/1

x!=-5

x∈R



We add all the numbers together, and all the variables

(2x-1)/x-((3x-2)/5-x)-2=0

We calculate fractions


(10x-x)-5)/(5x-x))+(-((3x-2)*x)/(5x-x))-2=0

We add all the numbers together, and all the variables

(+9x)+4x))+(-((3x-2)*x)/(+4x))-2-5)/(=0

We get rid of parentheses

9x+4x))+(-((3x-2)*x)/(+4x))-2-5)/(=0

We multiply all the terms by the denominator


9x*(+4x))+(-((3x-2)*x)+4x))-2-5)=0



We calculate terms in parentheses: -((3x-2)*x), so:

(3x-2)*x

We multiply parentheses

3x^2-2x

Back to the equation:

-(3x^2-2x)



We get rid of parentheses

-3x^2+9x*(+4x))+(+2x+4x))-2-5)=0

We add all the numbers together, and all the variables

-3x^2+9x*(+4x))+(+6x))-2-5)=0

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