2(x-3)=6-5(x+1)

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Solution for 2(x-3)=6-5(x+1) equation: 



2(x-3)=6-5(x+1)

We move all terms to the left:

2(x-3)-(6-5(x+1))=0

We multiply parentheses

2x-(6-5(x+1))-6=0



We calculate terms in parentheses: -(6-5(x+1)), so:

6-5(x+1)

determiningTheFunctionDomain
-5(x+1)+6

We multiply parentheses

-5x-5+6

We add all the numbers together, and all the variables

-5x+1

Back to the equation:

-(-5x+1)



We get rid of parentheses

2x+5x-1-6=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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