(x)/(x+2)-3=(1)/(x+2)

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Solution for (x)/(x+2)-3=(1)/(x+2) equation: 



(x)/(x+2)-3=(1)/(x+2)

We move all terms to the left:

(x)/(x+2)-3-((1)/(x+2))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x+2))!=0

x∈R



We calculate fractions


3x^2/((x+2)*(x+2)))+(-(1*(x+2))/((x+2)*(x+2)))-3=0

We calculate fractions


(3x^2*((x+2)*(x+2)))-3)/(((x+2)*(x+2)))+(*((x+2)*(x+2)))-3)+(-(1*(x+2))*((x+2)*(x+2)))+()/(((x+2)*(x+2)))+(*((x+2)*(x+2)))-3)=0



We calculate terms in parentheses: +(3x^2*((x+2)*(x+2))), so:

3x^2*((x+2)*(x+2))



We can not solve this equation

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