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(3x+1)=(2x+-2)
We move all terms to the left:
(3x+1)-((2x+-2))=0
We add all the numbers together, and all the variables
(3x+1)-((2x-2))=0
We get rid of parentheses
3x-((2x-2))+1=0
We calculate terms in parentheses: -((2x-2)), so:We get rid of parentheses
(2x-2)
We get rid of parentheses
2x-2
Back to the equation:
-(2x-2)
3x-2x+2+1=0
We add all the numbers together, and all the variables
x+3=0
We move all terms containing x to the left, all other terms to the right
x=-3
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