x2-9x+71=7x+7

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Solution for x2-9x+71=7x+7 equation: 



x2-9x+71=7x+7

We move all terms to the left:

x2-9x+71-(7x+7)=0

We add all the numbers together, and all the variables

x^2-9x-(7x+7)+71=0

We get rid of parentheses

x^2-9x-7x-7+71=0

We add all the numbers together, and all the variables

x^2-16x+64=0

a = 1; b = -16; c = +64;
Δ = b2-4ac
Δ = -162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{2}=8$

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