3y-7+2(5y+3)=-5(y+1)

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Solution for 3y-7+2(5y+3)=-5(y+1) equation: 



3y-7+2(5y+3)=-5(y+1)

We move all terms to the left:

3y-7+2(5y+3)-(-5(y+1))=0

We multiply parentheses

3y+10y-(-5(y+1))+6-7=0



We calculate terms in parentheses: -(-5(y+1)), so:

-5(y+1)

We multiply parentheses

-5y-5

Back to the equation:

-(-5y-5)



We add all the numbers together, and all the variables

13y-(-5y-5)-1=0

We get rid of parentheses

13y+5y+5-1=0

We add all the numbers together, and all the variables

18y+4=0

We move all terms containing y to the left, all other terms to the right

18y=-4

y=-4/18

y=-2/9

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