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16=4+3(a+2)
We move all terms to the left:
16-(4+3(a+2))=0
We calculate terms in parentheses: -(4+3(a+2)), so:We get rid of parentheses
4+3(a+2)
determiningTheFunctionDomain 3(a+2)+4
We multiply parentheses
3a+6+4
We add all the numbers together, and all the variables
3a+10
Back to the equation:
-(3a+10)
-3a-10+16=0
We add all the numbers together, and all the variables
-3a+6=0
We move all terms containing a to the left, all other terms to the right
-3a=-6
a=-6/-3
a=+2
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