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(2x+14)(4x-26)=0
We multiply parentheses ..
(+8x^2-52x+56x-364)=0
We get rid of parentheses
8x^2-52x+56x-364=0
We add all the numbers together, and all the variables
8x^2+4x-364=0
a = 8; b = 4; c = -364;
Δ = b2-4ac
Δ = 42-4·8·(-364)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-108}{2*8}=\frac{-112}{16} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+108}{2*8}=\frac{104}{16} =6+1/2 $
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