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3b^2-4b-84=0
a = 3; b = -4; c = -84;
Δ = b2-4ac
Δ = -42-4·3·(-84)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-32}{2*3}=\frac{-28}{6} =-4+2/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+32}{2*3}=\frac{36}{6} =6 $
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