4m2+6m-4=0

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Solution for 4m2+6m-4=0 equation: 



4m^2+6m-4=0

a = 4; b = 6; c = -4;
Δ = b2-4ac
Δ = 62-4·4·(-4)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-10}{2*4}=\frac{-16}{8}
=-2
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+10}{2*4}=\frac{4}{8}
=1/2
$

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