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x2(x+1)=3(4-x)
We move all terms to the left:
x2(x+1)-(3(4-x))=0
We add all the numbers together, and all the variables
x2(x+1)-(3(-1x+4))=0
We multiply parentheses
x^3+x^2-(3(-1x+4))=0
We calculate terms in parentheses: -(3(-1x+4)), so:We do not support expression: x^3
3(-1x+4)
We multiply parentheses
-3x+12
Back to the equation:
-(-3x+12)
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